| |
one method is to have:?y*/w
9 8 7 6 5 9 8 7 6 5 maps to
甲乙丙丁戊己庚辛壬癸:YP<
and©緣生術數研究社 -- 術數研究 oF
9 8 7 6 5 4 9 8 7 6 5 4 maps to?L{qRT
子丑寅卯辰巳午未 申酉 戌亥
then e.g. forX
甲子乙丑, add them together, gets 9+8+9+8 = 34.jS
divided by 5, remainder is 4, and then, I forgot ... but it's documented in many books.#$.|u<
©緣生術數研究社 -- 術數研究 4F&dD
the 2nd method is based on previous method, and using the "palm" to aid the calculation, and should be able to count the result within 2-5 seconds. It's quite hard for me to illustrate here though ... it's maths, anyway. not hard to derive oneself. This method is documented in 1 or 2 books only -- the books I have read so far.z
©緣生術數研究社 -- 術數研究 V
But I have to admit that if you have good memory, 方法一 is a good way.A[$d
©緣生術數研究社 -- 術數研究 Mm0tn
And finally, my suggestion is, to prepare a cheat-sheet ... or, save it in PDA...vjQ7=
| | |
|
|
|
頂端 
加到"我的最愛"
主題管理：
總固頂 
取消總固頂 
短訊息
查看
搜尋
通訊錄
引用
回覆
只看我
2006/03/12 09:37am 
IP: 已設定保密
mFm$EU