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one method is to have:'S 9 8 7 6 5 9 8 7 6 5 maps to
¥Ò¤A¤þ¤B¥³¤v©°¨¯¤Ð¬ÑIV?mp and©½t¥Í³N¼Æ¬ã¨sªÀ -- ³N¼Æ¬ã¨s¡@¡@ *Erqd 9 8 7 6 5 4 9 8 7 6 5 4 maps to<ob7|T ¤l¤¡±G¥f¨°¤x¤È¥¼ ¥Ó¨» ¦¦¥è
then e.g. forc ¥Ò¤l¤A¤¡, add them together, gets 9+8+9+8 = 34.5E divided by 5, remainder is 4, and then, I forgot ... but it's documented in many books.$" ©½t¥Í³N¼Æ¬ã¨sªÀ -- ³N¼Æ¬ã¨s¡@¡@ V the 2nd method is based on previous method, and using the "palm" to aid the calculation, and should be able to count the result within 2-5 seconds. It's quite hard for me to illustrate here though ... it's maths, anyway. not hard to derive oneself. This method is documented in 1 or 2 books only -- the books I have read so far.Hxi~/ ©½t¥Í³N¼Æ¬ã¨sªÀ -- ³N¼Æ¬ã¨s¡@¡@ _D But I have to admit that if you have good memory, ¤èªk¤@ is a good way..gXmsj ©½t¥Í³N¼Æ¬ã¨sªÀ -- ³N¼Æ¬ã¨s¡@¡@ g8<[ And finally, my suggestion is, to prepare a cheat-sheet ... or, save it in PDA...rkz1.g
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