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one method is to have:'S
9 8 7 6 5 9 8 7 6 5 maps to
甲乙丙丁戊己庚辛壬癸IV?mp
and©緣生術數研究社 -- 術數研究 *Erqd
9 8 7 6 5 4 9 8 7 6 5 4 maps to<ob7|T
子丑寅卯辰巳午未 申酉 戌亥
then e.g. forc
甲子乙丑, add them together, gets 9+8+9+8 = 34.5E
divided by 5, remainder is 4, and then, I forgot ... but it's documented in many books.$"
©緣生術數研究社 -- 術數研究 V
the 2nd method is based on previous method, and using the "palm" to aid the calculation, and should be able to count the result within 2-5 seconds. It's quite hard for me to illustrate here though ... it's maths, anyway. not hard to derive oneself. This method is documented in 1 or 2 books only -- the books I have read so far.Hxi~/
©緣生術數研究社 -- 術數研究 _D
But I have to admit that if you have good memory, 方法一 is a good way..gXmsj
©緣生術數研究社 -- 術數研究 g8<[
And finally, my suggestion is, to prepare a cheat-sheet ... or, save it in PDA...rkz1.g
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2006/03/12 09:37am 
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8$